Example 18 Solve the following pair of equations by reducing them to a pair of linear equations 5/(𝑥 −1) 1/(𝑦 −2) = 2 6/(𝑥 −1) – 3/(𝑦 −2) = 1 5/(𝑥 − 1) 1/(𝑦 − 2) = 2 6/(𝑥 − 1) – 3/(𝑦 − 2) = 1 So, our equations become 5u v = 2 6u – 3v = 1 Thus, our The Soln Set ={(1,4),(4,1)} Subing y=x3 in the first eqn to get x^2(x3)^2=17, or, 2x^26x917=0, ie, x^23x4=0 rArr (x1)(x4)=0 rArr x=1, x=4 ThenCalled the geometric distribution, and are related by Y = X −1 4 Poisson distribution with mean (and variance) λ With λ > 0 a constant, X has pmf
Ncert Solutions For Class 9 Maths Chapter 4 Linear Equations In Two Variables
2^x 3^y=17 2^x 2-3^y 1=5