Ex 2 1 14 Mcq Find Value Of Tan 1 Root 3 Sec 1 2 Video
Berdasarkan Hukum pembiasan Snellius 𝑛′𝑠𝑖𝑛 𝑖 2 = 𝑛 𝑠𝑖𝑛 𝑖 1 Untuk sudut yang sangat kecil maka 𝑛′ 𝑖 2 = 𝑛 𝑖 1 Karena 𝑖 3 = 𝑖 1 , 𝑖 3 = 2𝑖 2 , maka 𝑖 1 = 2𝑖 2 , jadi 𝑛′ = 2𝑛 = 8/3 4627x31=0 Three solutions were found x = (3√27)/18= (1i√ 3 )/6= i x = (3√27)/18= (1i√ 3 )/6= i x = 1/3 = 0333 Step by step solution Step 1 Equation